**Python Program to Check Leap Year**: In this program, we will learn to check whether a year is **leap year** or not. We will use nested if…else to solve this problem.

A leap year is exactly divisible by 4 except for century years (years ending with 00). The century year is a leap year only if it is perfectly divisible by 400. For example,

2017is not a leap year1900is a not leap year2012is a leap year2000is a leap year

**Python Program to Check Leap Year**

**Source Code**

```
# Python program to check if year is a leap year or not
year = 2000
# To get year (integer input) from the user
# year = int(input("Enter a year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
else:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
```

**Output of Program**