Python program for removing i-th character from a string

Given the string, we have to remove the ith indexed character from the string.

In any string, indexing always start from 0. Suppose we have a string geeks then its indexing will be as –

g e e k s
0 1 2 3 4

Examples :

Input : Geek
        i = 1
Output : Gek 

Input : Peter 
        i = 4
Output : Pete

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach 1 : From the given string, i-th indexed element has to be removed. So, Split the string into two halves, before indexed character and after indexed character. Return the merged string.

Below is the implementation of above approach :

Python3 program for removing i-th

indexed character from a string

Removes character at index i

def remove(string, i):

# Characters before the i-th indexed
# is stored in a variable a
a = string[ : i]

# Characters after the nth indexed
# is stored in a variable b
b = string[i + 1: ]

# Returning string after removing
# nth indexed character.
return a + b

Driver Code

if name == ‘main‘:

string = "geeksFORgeeks"

# Remove nth index element
i = 5

# Print the new string
print(remove(string, i))

Output:

geeksORgeeks

Approach 2 : The idea is to use string replace in Python

Python3 program for removing i-th

indexed character from a string

Removes character at index i

def remove(string, i):

for j in range(len(string)):
    if j == i:
        string = string.replace(string[i], "", 1)
return string

Driver Code

if name == ‘main‘:

string = "geeksFORgeeks"

# Remove nth index element
i = 5

# Print the new string
print(remove(string, i))

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