# Python Dictionary to find mirror characters in a string

Given a string and a number N, we need: to mirror the characters from the N-th position up to the length of the string in alphabetical order. In mirror operation, we change ‘a’ to ‘z’, ‘b’ to ‘y’, and so on.
Examples:

```Input : N = 3
Output : paizwlc
We mirror characters from position 3 to end.

Input : N = 6
pneumonia
Output : pneumlmrz```

Recommended: Please try your approach on {IDE} first, before moving on to the solution.
We have an existing solution for this problem please refer to Mirror characters of a string link. We can solve this problem in Python using Dictionary Data Structure. The mirror value of ‘a’ is ‘z’,’b’ is ‘y’, etc, so we create a dictionary data structure and one-to-one map reverse sequence of alphabets onto the original sequence of alphabets. Now traverse characters from length k in given string and change characters into their mirror value using a dictionary.

``````# function to mirror characters of a string

def mirrorChars(input,k):

# create dictionary
original = 'abcdefghijklmnopqrstuvwxyz'
reverse = 'zyxwvutsrqponmlkjihgfedcba'
dictChars = dict(zip(original,reverse))

# separate out string after length k to change
# characters in mirror
prefix = input[0:k-1]
suffix = input[k-1:]
mirror = ''

# change into mirror
for i in range(0,len(suffix)):
mirror = mirror + dictChars[suffix[i]]

# concat prefix and mirrored part
print (prefix+mirror)

# Driver program
if __name__ == "__main__":
`paizwlc`