# Python | Check if a given string is binary string or not

Given a string str. The task is to check whether it is a binary string or not.
Examples:

```Input: str = "01010101010"
Output: Yes

Input: str = "geeks101"
Output: No```

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach 1: Using Set

1. Insert the given string in a set
2. Check if the set characters consist of 1 and/or 0 only.

## string is accepted or not

def check(string) :

``````# set function convert string
# into set of characters .
p = set(string)

# declare set of '0', '1' .
s = {'0', '1'}

# check set p is same as set s
# or set p contains only '0'
# or set p contains only '1'
# or not, if any one condition
# is true then string is accepted
# otherwise not .
if s == p or p == {'0'} or p == {'1'}:
print("Yes")
else :
print("No")``````

## driver code

if name == “main” :

``````string = "101010000111"

# function calling
check(string)``````

Output

`Yes`

Approach 2: Simple Iteration

1. Iterate for every character and check if the character is 0 or 1.
2. If it is not then set a counter and break.
3. After iteration check whether the counter is set or not.

## string is accepted or not

def check2(string) :

``````# initialize the variable t
# with '01' string
t = '01'

# initialize the variable count
# with 0 value
count = 0

# looping through each character
# of the string .
for char in string :

# check the character is present in
# string t or not.
# if this condition is true
# assign 1 to the count variable
# and break out of the for loop
# otherwise pass
if char not in t :
count = 1
break
else :
pass

# after coming out of the loop
# check value of count is non-zero or not
# if the value is non-zero the en condition is true
# and string is not accepted
# otherwise string is accepted
if count :
print("No")
else :
print("Yes")``````

## driver code

if name == “main” :

``````string = "001021010001010"

# function calling
check2(string)``````

Output

`No`

Approach 3Regular Expressions

1. Compile a regular expression using compile() for “character is not 0 or 1”.
2. Use re.findall() to fetch the strings satisfying the above regular expression.
3. Print output based on the result.
• Python3

## import library

import re

sampleInput = “1001010”

## which have characters other than 0 and 1

c = re.compile(‘[^01]’)

## that have characters other than 0 and 1.

if(len(c.findall(sampleInput))):
print(“No”) # if length of list > 0 then it is not binary
else:
print(“Yes”) # if length of list = 0 then it is binary

Output

`Yes`