Find the largest in a sequence of 10 numbers in Java

(Find the Largest Number) The process of finding the largest value is used frequently in computer applications. For example, a program that determines the winner of a sales contest would input the number of units sold by each salesperson. The salesperson who sells the most units wins the contest. Write a pseudo code program, then a Java application that inputs a series of 10 integers and determines and prints the largest integer. Your program should use at least the following three variables:
a) counter: A counter to count to 10 (i.e., to keep track of how many numbers have been
input and to determine when all 10 numbers have been processed).
b) number: The integer most recently input by the user.
c) largest: The largest number found so far.

Find the Largest Number in Java Program

LargestNumber.java

/*
 *       Filename:  LargestNumber.java
 *
 *    Description:  Exercise 4.21 - Find the Largest Number
 *
*  @Author:  Bilal Tahir Khan Meo
 *  Website: https://www.codeblah.com
 *
 * =====================================================================================
 */
public class LargestNumber{
    int largest = 0;

    public void enterNumber(int x){
        largest = Math.max(x, largest);
    }
    public int getLargestNumber(){
        return largest;
    }
}

LargestNumberTest.java

/*
 *       Filename:  LargestNumberTest.java
 *
 *    Description:  4.21 - Find the largest in a sequence of 10 numbers
 *
 *  @Author:  Bilal Tahir Khan Meo
 *  Website: https://www.codeblah.com
 *
 * =====================================================================================
 */
import java.util.Scanner;

public class LargestNumberTest{
    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        LargestNumber ln = new LargestNumber();

        for(int i=0; i<10; i++){
            System.out.printf("%d/10. Enter a number: ", i+1);
            ln.enterNumber(sc.nextInt());
        }
        System.out.printf("The largest number is: %d\n", ln.getLargestNumber());
    }
}